Base | Representation |
---|---|
bin | 1010000001101000110011… |
… | …1001101011101101001001 |
3 | 1110000210221020122201021001 |
4 | 2200122030321223231021 |
5 | 2421101104000404001 |
6 | 35240002224015001 |
7 | 2215255261060642 |
oct | 240321471535511 |
9 | 43023836581231 |
10 | 11023250013001 |
11 | 356aa30290896 |
12 | 12a0468161461 |
13 | 61c64622b7b5 |
14 | 2a17573446c9 |
15 | 141b17902001 |
hex | a068ce6bb49 |
11023250013001 has 12 divisors (see below), whose sum is σ = 11712285383040. Its totient is φ = 10372638536000.
The previous prime is 11023250012941. The next prime is 11023250013011. The reversal of 11023250013001 is 10031005232011.
It is not a de Polignac number, because 11023250013001 - 227 = 11023115795273 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11023250013001.
It is not an unprimeable number, because it can be changed into a prime (11023250013011) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2641141 + ... + 5387218.
It is an arithmetic number, because the mean of its divisors is an integer number (976023781920).
Almost surely, 211023250013001 is an apocalyptic number.
It is an amenable number.
11023250013001 is a deficient number, since it is larger than the sum of its proper divisors (689035370039).
11023250013001 is an equidigital number, since it uses as much as digits as its factorization.
11023250013001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8033144 (or 8033127 counting only the distinct ones).
The product of its (nonzero) digits is 180, while the sum is 19.
Adding to 11023250013001 its reverse (10031005232011), we get a palindrome (21054255245012).
The spelling of 11023250013001 in words is "eleven trillion, twenty-three billion, two hundred fifty million, thirteen thousand, one".
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