Base | Representation |
---|---|
bin | 10000000010101000000… |
… | …011011110001001110011 |
3 | 10220101022100110102111021 |
4 | 100002220003132021303 |
5 | 121030033231010003 |
6 | 2202223125200311 |
7 | 142432535556424 |
oct | 20025003361163 |
9 | 3811270412437 |
10 | 1102331110003 |
11 | 3955501a0492 |
12 | 159780560097 |
13 | 7cc45a236c6 |
14 | 3b4d2d1364b |
15 | 1da1a46a2bd |
hex | 100a80de273 |
1102331110003 has 2 divisors, whose sum is σ = 1102331110004. Its totient is φ = 1102331110002.
The previous prime is 1102331109991. The next prime is 1102331110019. The reversal of 1102331110003 is 3000111332011.
It is an a-pointer prime, because the next prime (1102331110019) can be obtained adding 1102331110003 to its sum of digits (16).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1102331110003 is a prime.
It is a super-5 number, since 5×11023311100035 (a number of 61 digits) contains 55555 as substring.
It is not a weakly prime, because it can be changed into another prime (1102331110703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551165555001 + 551165555002.
It is an arithmetic number, because the mean of its divisors is an integer number (551165555002).
Almost surely, 21102331110003 is an apocalyptic number.
1102331110003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102331110003 is an equidigital number, since it uses as much as digits as its factorization.
1102331110003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1102331110003 its reverse (3000111332011), we get a palindrome (4102442442014).
The spelling of 1102331110003 in words is "one trillion, one hundred two billion, three hundred thirty-one million, one hundred ten thousand, three".
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