11023313001 has 4 divisors (see below), whose sum is σ = 14697750672. Its totient is φ = 7348875332.

The previous prime is 11023312987. The next prime is 11023313027. The reversal of 11023313001 is 10031332011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11023313001 - 2⁵ = 11023312969 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11023313051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1837218831 + ... + 1837218836.

It is an arithmetic number, because the mean of its divisors is an integer number (3674437668).

Almost surely, 2^11023313001 is an apocalyptic number.

It is an amenable number.

11023313001 is a deficient number, since it is larger than the sum of its proper divisors (3674437671).

11023313001 is an equidigital number, since it uses as much as digits as its factorization.

11023313001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3674437670.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11023313001 its reverse (10031332011), we get a palindrome (21054645012).

The spelling of 11023313001 in words is "eleven billion, twenty-three million, three hundred thirteen thousand, one".