Base | Representation |
---|---|
bin | 110011010101011110… |
… | …0101010110110000101 |
3 | 101112112222011200111022 |
4 | 1212222330222312011 |
5 | 3301234001311003 |
6 | 122351121120525 |
7 | 10651622231354 |
oct | 1465274526605 |
9 | 345488150438 |
10 | 110242213253 |
11 | 42831945557 |
12 | 19447a89145 |
13 | a51b744263 |
14 | 549b43399b |
15 | 2d034de738 |
hex | 19aaf2ad85 |
110242213253 has 2 divisors, whose sum is σ = 110242213254. Its totient is φ = 110242213252.
The previous prime is 110242213177. The next prime is 110242213267. The reversal of 110242213253 is 352312242011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 104727962689 + 5514250564 = 323617^2 + 74258^2 .
It is an emirp because it is prime and its reverse (352312242011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110242213253 - 210 = 110242212229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110242293253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55121106626 + 55121106627.
It is an arithmetic number, because the mean of its divisors is an integer number (55121106627).
Almost surely, 2110242213253 is an apocalyptic number.
It is an amenable number.
110242213253 is a deficient number, since it is larger than the sum of its proper divisors (1).
110242213253 is an equidigital number, since it uses as much as digits as its factorization.
110242213253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 110242213253 its reverse (352312242011), we get a palindrome (462554455264).
The spelling of 110242213253 in words is "one hundred ten billion, two hundred forty-two million, two hundred thirteen thousand, two hundred fifty-three".
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