Base | Representation |
---|---|
bin | 11001000100001111010111… |
… | …011101011100000111100111 |
3 | 112110100002021012002221221022 |
4 | 121010033113131130013213 |
5 | 103422203210320431343 |
6 | 1030244420210241355 |
7 | 32135521631116562 |
oct | 3104172735340747 |
9 | 473302235087838 |
10 | 110242540405223 |
11 | 32143665050486 |
12 | 104458ab88625b |
13 | 4968a99a7b435 |
14 | 1d31aa5b5b4d9 |
15 | cb29dc6cb568 |
hex | 6443d775c1e7 |
110242540405223 has 2 divisors, whose sum is σ = 110242540405224. Its totient is φ = 110242540405222.
The previous prime is 110242540405147. The next prime is 110242540405253. The reversal of 110242540405223 is 322504045242011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110242540405223 - 28 = 110242540404967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110242540405253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55121270202611 + 55121270202612.
It is an arithmetic number, because the mean of its divisors is an integer number (55121270202612).
Almost surely, 2110242540405223 is an apocalyptic number.
110242540405223 is a deficient number, since it is larger than the sum of its proper divisors (1).
110242540405223 is an equidigital number, since it uses as much as digits as its factorization.
110242540405223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76800, while the sum is 35.
Adding to 110242540405223 its reverse (322504045242011), we get a palindrome (432746585647234).
The spelling of 110242540405223 in words is "one hundred ten trillion, two hundred forty-two billion, five hundred forty million, four hundred five thousand, two hundred twenty-three".
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