Base | Representation |
---|---|
bin | 1010000001101100110001… |
… | …0100011110001010100111 |
3 | 1110000220200101201212002101 |
4 | 2200123030110132022213 |
5 | 2421110243341000124 |
6 | 35240255552552531 |
7 | 2215323530602654 |
oct | 240331424361247 |
9 | 43026611655071 |
10 | 11024314000039 |
11 | 357042693901a |
12 | 12a0704552747 |
13 | 61c7857b0622 |
14 | 2a181878ac2b |
15 | 141b7b022644 |
hex | a06cc51e2a7 |
11024314000039 has 2 divisors, whose sum is σ = 11024314000040. Its totient is φ = 11024314000038.
The previous prime is 11024314000019. The next prime is 11024314000043. The reversal of 11024314000039 is 93000041342011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11024314000039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11024313999980 and 11024314000016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11024314000019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5512157000019 + 5512157000020.
It is an arithmetic number, because the mean of its divisors is an integer number (5512157000020).
Almost surely, 211024314000039 is an apocalyptic number.
11024314000039 is a deficient number, since it is larger than the sum of its proper divisors (1).
11024314000039 is an equidigital number, since it uses as much as digits as its factorization.
11024314000039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 28.
The spelling of 11024314000039 in words is "eleven trillion, twenty-four billion, three hundred fourteen million, thirty-nine", and thus it is an aban number.
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