Base | Representation |
---|---|
bin | 1010000001101100110010… |
… | …1100100011101100100111 |
3 | 1110000220200211121122102101 |
4 | 2200123030230203230213 |
5 | 2421110302000023101 |
6 | 35240300340152531 |
7 | 2215323635351314 |
oct | 240331454435447 |
9 | 43026624548371 |
10 | 11024320314151 |
11 | 357042a4609a1 |
12 | 12a0706698747 |
13 | 61c786bb15a1 |
14 | 2a1819551d0b |
15 | 141b7b86d401 |
hex | a06ccb23b27 |
11024320314151 has 2 divisors, whose sum is σ = 11024320314152. Its totient is φ = 11024320314150.
The previous prime is 11024320314103. The next prime is 11024320314157. The reversal of 11024320314151 is 15141302342011.
It is a strong prime.
It is an emirp because it is prime and its reverse (15141302342011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11024320314151 - 27 = 11024320314023 is a prime.
It is a super-3 number, since 3×110243203141513 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11024320314157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5512160157075 + 5512160157076.
It is an arithmetic number, because the mean of its divisors is an integer number (5512160157076).
Almost surely, 211024320314151 is an apocalyptic number.
11024320314151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11024320314151 is an equidigital number, since it uses as much as digits as its factorization.
11024320314151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 11024320314151 its reverse (15141302342011), we get a palindrome (26165622656162).
The spelling of 11024320314151 in words is "eleven trillion, twenty-four billion, three hundred twenty million, three hundred fourteen thousand, one hundred fifty-one".
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