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1102450143103 = 43152316834127
BaseRepresentation
bin10000000010101111001…
…001100010111101111111
310220101121122102221012121
4100002233021202331333
5121030304214034403
62202243020343411
7142435512412621
oct20025711427577
93811548387177
101102450143103
11395601401851
121597b43a4b67
137cc6459c4aa
143b504a5ac11
151da25b2e3bd
hex100af262f7f

1102450143103 has 8 divisors (see below), whose sum is σ = 1128829287168. Its totient is φ = 1076104670424.

The previous prime is 1102450143083. The next prime is 1102450143227. The reversal of 1102450143103 is 3013410542011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1102450143103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1102450113103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8351575 + ... + 8482552.

It is an arithmetic number, because the mean of its divisors is an integer number (141103660896).

Almost surely, 21102450143103 is an apocalyptic number.

1102450143103 is a deficient number, since it is larger than the sum of its proper divisors (26379144065).

1102450143103 is a wasteful number, since it uses less digits than its factorization.

1102450143103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16835693.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1102450143103 its reverse (3013410542011), we get a palindrome (4115860685114).

The spelling of 1102450143103 in words is "one trillion, one hundred two billion, four hundred fifty million, one hundred forty-three thousand, one hundred three".

Divisors: 1 43 1523 65489 16834127 723867461 25638375421 1102450143103