Base | Representation |
---|---|
bin | 10100100010010010… |
… | …00011001001100001 |
3 | 1001110100111012001100 |
4 | 22101021003021201 |
5 | 140034400044410 |
6 | 5022000025013 |
7 | 540131660124 |
oct | 122111031141 |
9 | 31410435040 |
10 | 11025003105 |
11 | 4748366016 |
12 | 2178302169 |
13 | 106917009c |
14 | 76833c3bb |
15 | 447d7c8c0 |
hex | 291243261 |
11025003105 has 24 divisors (see below), whose sum is σ = 19113742440. Its totient is φ = 5878851840.
The previous prime is 11025002971. The next prime is 11025003107. The reversal of 11025003105 is 50130052011.
It can be written as a sum of positive squares in 4 ways, for example, as 6588244224 + 4436758881 = 81168^2 + 66609^2 .
It is not a de Polignac number, because 11025003105 - 222 = 11020808801 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (11025003107) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 240901 + ... + 282989.
It is an arithmetic number, because the mean of its divisors is an integer number (796405935).
Almost surely, 211025003105 is an apocalyptic number.
11025003105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11025003105 is a deficient number, since it is larger than the sum of its proper divisors (8088739335).
11025003105 is a wasteful number, since it uses less digits than its factorization.
11025003105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47921 (or 47918 counting only the distinct ones).
The product of its (nonzero) digits is 150, while the sum is 18.
Adding to 11025003105 its reverse (50130052011), we get a palindrome (61155055116).
The spelling of 11025003105 in words is "eleven billion, twenty-five million, three thousand, one hundred five".
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