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1102915312981 is a prime number
BaseRepresentation
bin10000000011001010111…
…000000001110101010101
310220102211001202000022121
4100003022320001311111
5121032232310003411
62202401114455541
7142453161323206
oct20031270016525
93812731660277
101102915312981
1139581aa39869
121599041345b1
1380009a7ac41
143b54a7475ad
151da518b7571
hex100cae01d55

1102915312981 has 2 divisors, whose sum is σ = 1102915312982. Its totient is φ = 1102915312980.

The previous prime is 1102915312963. The next prime is 1102915312997. The reversal of 1102915312981 is 1892135192011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1023872801956 + 79042511025 = 1011866^2 + 281145^2 .

It is an emirp because it is prime and its reverse (1892135192011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1102915312981 - 25 = 1102915312949 is a prime.

It is a super-2 number, since 2×11029153129812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1102915315981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551457656490 + 551457656491.

It is an arithmetic number, because the mean of its divisors is an integer number (551457656491).

Almost surely, 21102915312981 is an apocalyptic number.

It is an amenable number.

1102915312981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1102915312981 is an equidigital number, since it uses as much as digits as its factorization.

1102915312981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 43.

The spelling of 1102915312981 in words is "one trillion, one hundred two billion, nine hundred fifteen million, three hundred twelve thousand, nine hundred eighty-one".