Base | Representation |
---|---|
bin | 1010000010000010110001… |
… | …0110011101111011101011 |
3 | 1110001110221000002222210102 |
4 | 2200200230112131323223 |
5 | 2421204342321302103 |
6 | 35243114013140015 |
7 | 2215623064626134 |
oct | 240405426357353 |
9 | 43043830088712 |
10 | 11030220103403 |
11 | 3572987766986 |
12 | 12a189248a60b |
13 | 6201b7291947 |
14 | 2a1c18d16c8b |
15 | 141dc47ade88 |
hex | a082c59deeb |
11030220103403 has 2 divisors, whose sum is σ = 11030220103404. Its totient is φ = 11030220103402.
The previous prime is 11030220103387. The next prime is 11030220103423. The reversal of 11030220103403 is 30430102203011.
11030220103403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an a-pointer prime, because the next prime (11030220103423) can be obtained adding 11030220103403 to its sum of digits (20).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11030220103403 - 24 = 11030220103387 is a prime.
It is not a weakly prime, because it can be changed into another prime (11030220103423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515110051701 + 5515110051702.
It is an arithmetic number, because the mean of its divisors is an integer number (5515110051702).
Almost surely, 211030220103403 is an apocalyptic number.
11030220103403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11030220103403 is an equidigital number, since it uses as much as digits as its factorization.
11030220103403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 11030220103403 its reverse (30430102203011), we get a palindrome (41460322306414).
The spelling of 11030220103403 in words is "eleven trillion, thirty billion, two hundred twenty million, one hundred three thousand, four hundred three".
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