Base | Representation |
---|---|
bin | 1010000010000011000111… |
… | …0001101001001100100111 |
3 | 1110001111011100100210012011 |
4 | 2200200301301221030213 |
5 | 2421210034121113021 |
6 | 35243131023535051 |
7 | 2215625251326544 |
oct | 240406161511447 |
9 | 43044140323164 |
10 | 11030311113511 |
11 | 3572a24078148 |
12 | 12a18b8a5a487 |
13 | 6202000a8591 |
14 | 2a1c27047bcb |
15 | 141dcc789de1 |
hex | a0831c69327 |
11030311113511 has 2 divisors, whose sum is σ = 11030311113512. Its totient is φ = 11030311113510.
The previous prime is 11030311113467. The next prime is 11030311113557. The reversal of 11030311113511 is 11531111303011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11030311113511 is a prime.
It is a super-3 number, since 3×110303111135113 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11030311113581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515155556755 + 5515155556756.
It is an arithmetic number, because the mean of its divisors is an integer number (5515155556756).
Almost surely, 211030311113511 is an apocalyptic number.
11030311113511 is a deficient number, since it is larger than the sum of its proper divisors (1).
11030311113511 is an equidigital number, since it uses as much as digits as its factorization.
11030311113511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 135, while the sum is 22.
Adding to 11030311113511 its reverse (11531111303011), we get a palindrome (22561422416522).
The spelling of 11030311113511 in words is "eleven trillion, thirty billion, three hundred eleven million, one hundred thirteen thousand, five hundred eleven".
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