Base | Representation |
---|---|
bin | 1010000010000011110101… |
… | …0110110101011101101111 |
3 | 1110001111122212222012020122 |
4 | 2200200331112311131233 |
5 | 2421210433341144323 |
6 | 35243202204235155 |
7 | 2215633131001025 |
oct | 240407526653557 |
9 | 43044585865218 |
10 | 11030505412463 |
11 | 3573013816899 |
12 | 12a1951b3babb |
13 | 620231417984 |
14 | 2a1c44b84715 |
15 | 141dde869ec8 |
hex | a083d5b576f |
11030505412463 has 4 divisors (see below), whose sum is σ = 11031815612760. Its totient is φ = 11029195212168.
The previous prime is 11030505412403. The next prime is 11030505412477. The reversal of 11030505412463 is 36421450503011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11030505412463 - 28 = 11030505412207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11030505412403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 655087520 + ... + 655104357.
It is an arithmetic number, because the mean of its divisors is an integer number (2757953903190).
Almost surely, 211030505412463 is an apocalyptic number.
11030505412463 is a deficient number, since it is larger than the sum of its proper divisors (1310200297).
11030505412463 is an equidigital number, since it uses as much as digits as its factorization.
11030505412463 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1310200296.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 11030505412463 its reverse (36421450503011), we get a palindrome (47451955915474).
The spelling of 11030505412463 in words is "eleven trillion, thirty billion, five hundred five million, four hundred twelve thousand, four hundred sixty-three".
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