Base | Representation |
---|---|
bin | 1010000010000101101011… |
… | …0101111010110110010011 |
3 | 1110001112221100210221022021 |
4 | 2200201122311322312103 |
5 | 2421212442011201433 |
6 | 35243323235152311 |
7 | 2215651315531324 |
oct | 240413265726623 |
9 | 43045840727267 |
10 | 11031000100243 |
11 | 3573247a85072 |
12 | 12a1a6b745697 |
13 | 6202aca5cb36 |
14 | 2a1c9075644b |
15 | 141e1ced422d |
hex | a085ad7ad93 |
11031000100243 has 2 divisors, whose sum is σ = 11031000100244. Its totient is φ = 11031000100242.
The previous prime is 11031000100213. The next prime is 11031000100249. The reversal of 11031000100243 is 34200100013011.
11031000100243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11031000100243 - 225 = 11030966545811 is a prime.
It is a super-3 number, since 3×110310001002433 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (11031000100249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515500050121 + 5515500050122.
It is an arithmetic number, because the mean of its divisors is an integer number (5515500050122).
Almost surely, 211031000100243 is an apocalyptic number.
11031000100243 is a deficient number, since it is larger than the sum of its proper divisors (1).
11031000100243 is an equidigital number, since it uses as much as digits as its factorization.
11031000100243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 11031000100243 its reverse (34200100013011), we get a palindrome (45231100113254).
The spelling of 11031000100243 in words is "eleven trillion, thirty-one billion, one hundred thousand, two hundred forty-three".
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