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11031011320130 = 2513937272129321
BaseRepresentation
bin1010000010000101101110…
…0000101110000101000010
31110001112222010220222002122
42200201123200232011002
52421213002344221010
635243324315444242
72215651513101344
oct240413340560502
943045863828078
1011031011320130
1135732533487aa
1212a1a73456682
136202b218aa19
142a1c92037294
15141e1de9d855
hexa085b82e142

11031011320130 has 32 divisors (see below), whose sum is σ = 20004043288320. Its totient is φ = 4379483168640.

The previous prime is 11031011320123. The next prime is 11031011320141. The reversal of 11031011320130 is 3102311013011.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11031011320099 and 11031011320108.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4115870 + ... + 6245190.

It is an arithmetic number, because the mean of its divisors is an integer number (625126352760).

Almost surely, 211031011320130 is an apocalyptic number.

11031011320130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11031011320130 is a deficient number, since it is larger than the sum of its proper divisors (8973031968190).

11031011320130 is a wasteful number, since it uses less digits than its factorization.

11031011320130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2133194.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11031011320130 its reverse (3102311013011), we get a palindrome (14133322333141).

The spelling of 11031011320130 in words is "eleven trillion, thirty-one billion, eleven million, three hundred twenty thousand, one hundred thirty".

Divisors: 1 2 5 10 139 278 695 1390 3727 7454 18635 37270 518053 1036106 2129321 2590265 4258642 5180530 10646605 21293210 295975619 591951238 1479878095 2959756190 7935979367 15871958734 39679896835 79359793670 1103101132013 2206202264026 5515505660065 11031011320130