Base | Representation |
---|---|
bin | 1010000010000101101110… |
… | …0000101110000101000010 |
3 | 1110001112222010220222002122 |
4 | 2200201123200232011002 |
5 | 2421213002344221010 |
6 | 35243324315444242 |
7 | 2215651513101344 |
oct | 240413340560502 |
9 | 43045863828078 |
10 | 11031011320130 |
11 | 35732533487aa |
12 | 12a1a73456682 |
13 | 6202b218aa19 |
14 | 2a1c92037294 |
15 | 141e1de9d855 |
hex | a085b82e142 |
11031011320130 has 32 divisors (see below), whose sum is σ = 20004043288320. Its totient is φ = 4379483168640.
The previous prime is 11031011320123. The next prime is 11031011320141. The reversal of 11031011320130 is 3102311013011.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11031011320099 and 11031011320108.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4115870 + ... + 6245190.
It is an arithmetic number, because the mean of its divisors is an integer number (625126352760).
Almost surely, 211031011320130 is an apocalyptic number.
11031011320130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11031011320130 is a deficient number, since it is larger than the sum of its proper divisors (8973031968190).
11031011320130 is a wasteful number, since it uses less digits than its factorization.
11031011320130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2133194.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11031011320130 its reverse (3102311013011), we get a palindrome (14133322333141).
The spelling of 11031011320130 in words is "eleven trillion, thirty-one billion, eleven million, three hundred twenty thousand, one hundred thirty".
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