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1103120130131 = 4597239965223
BaseRepresentation
bin10000000011010111000…
…101010110000001010011
310220110100100010210121222
4100003113011112001103
5121033142223131011
62202433312435255
7142461226252565
oct20032705260123
93813310123558
101103120130131
11395915611a38
12159960848b2b
1380040330a16
143b569a21335
151da64873ddb
hex100d7156053

1103120130131 has 4 divisors (see below), whose sum is σ = 1103360099952. Its totient is φ = 1102880160312.

The previous prime is 1103120130121. The next prime is 1103120130289. The reversal of 1103120130131 is 1310310213011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1103120130131 is a prime.

It is a super-2 number, since 2×11031201301312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1103120130121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119978015 + ... + 119987208.

It is an arithmetic number, because the mean of its divisors is an integer number (275840024988).

Almost surely, 21103120130131 is an apocalyptic number.

1103120130131 is a deficient number, since it is larger than the sum of its proper divisors (239969821).

1103120130131 is an equidigital number, since it uses as much as digits as its factorization.

1103120130131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 239969820.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1103120130131 its reverse (1310310213011), we get a palindrome (2413430343142).

The spelling of 1103120130131 in words is "one trillion, one hundred three billion, one hundred twenty million, one hundred thirty thousand, one hundred thirty-one".

Divisors: 1 4597 239965223 1103120130131