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1103140345232 = 2468946271577
BaseRepresentation
bin10000000011011000010…
…010011101010110010000
310220110101202011211112102
4100003120102131112100
5121033212412021412
62202435314015532
7142461563136002
oct20033022352620
93813352154472
101103140345232
11395925a69932
121599675775a8
138004458b013
143b56c5a4372
151da665188c2
hex100d849d590

1103140345232 has 10 divisors (see below), whose sum is σ = 2137334418918. Its totient is φ = 551570172608.

The previous prime is 1103140345213. The next prime is 1103140345243. The reversal of 1103140345232 is 2325430413011.

It can be written as a sum of positive squares in only one way, i.e., 928763948176 + 174376397056 = 963724^2 + 417584^2 .

It is a super-2 number, since 2×11031403452322 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1103140345195 and 1103140345204.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34473135773 + ... + 34473135804.

Almost surely, 21103140345232 is an apocalyptic number.

It is an amenable number.

1103140345232 is a deficient number, since it is larger than the sum of its proper divisors (1034194073686).

1103140345232 is an equidigital number, since it uses as much as digits as its factorization.

1103140345232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68946271585 (or 68946271579 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 1103140345232 its reverse (2325430413011), we get a palindrome (3428570758243).

The spelling of 1103140345232 in words is "one trillion, one hundred three billion, one hundred forty million, three hundred forty-five thousand, two hundred thirty-two".

Divisors: 1 2 4 8 16 68946271577 137892543154 275785086308 551570172616 1103140345232