Base | Representation |
---|---|
bin | 1010000010000111001111… |
… | …1101001010101100001111 |
3 | 1110001121000201121201211012 |
4 | 2200201303331022230033 |
5 | 2421214322341234133 |
6 | 35243433125515435 |
7 | 2215664623012463 |
oct | 240416375125417 |
9 | 43047021551735 |
10 | 11031421430543 |
11 | 3573443899828 |
12 | 12a1b68872b7b |
13 | 62034912c1c7 |
14 | 2a1cd06b04a3 |
15 | 141e44eacb48 |
hex | a0873f4ab0f |
11031421430543 has 2 divisors, whose sum is σ = 11031421430544. Its totient is φ = 11031421430542.
The previous prime is 11031421430527. The next prime is 11031421430581. The reversal of 11031421430543 is 34503412413011.
11031421430543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11031421430543 - 24 = 11031421430527 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11031421430443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515710715271 + 5515710715272.
It is an arithmetic number, because the mean of its divisors is an integer number (5515710715272).
Almost surely, 211031421430543 is an apocalyptic number.
11031421430543 is a deficient number, since it is larger than the sum of its proper divisors (1).
11031421430543 is an equidigital number, since it uses as much as digits as its factorization.
11031421430543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 11031421430543 its reverse (34503412413011), we get a palindrome (45534833843554).
The spelling of 11031421430543 in words is "eleven trillion, thirty-one billion, four hundred twenty-one million, four hundred thirty thousand, five hundred forty-three".
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