Base | Representation |
---|---|
bin | 1010000010001101001000… |
… | …0010111011101010000101 |
3 | 1110001202002201222101012120 |
4 | 2200203102002323222011 |
5 | 2421231041000001013 |
6 | 35244253520040153 |
7 | 2216052011435256 |
oct | 240432202735205 |
9 | 43052081871176 |
10 | 11033000000133 |
11 | 35740839634a1 |
12 | 12a2329463059 |
13 | 62053b1a0757 |
14 | 2a20001c6b2d |
15 | 141ed8877123 |
hex | a08d20bba85 |
11033000000133 has 4 divisors (see below), whose sum is σ = 14710666666848. Its totient is φ = 7355333333420.
The previous prime is 11033000000047. The next prime is 11033000000137. The reversal of 11033000000133 is 33100000033011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11033000000133 - 213 = 11032999991941 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11033000000137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1838833333353 + ... + 1838833333358.
It is an arithmetic number, because the mean of its divisors is an integer number (3677666666712).
Almost surely, 211033000000133 is an apocalyptic number.
It is an amenable number.
11033000000133 is a deficient number, since it is larger than the sum of its proper divisors (3677666666715).
11033000000133 is an equidigital number, since it uses as much as digits as its factorization.
11033000000133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3677666666714.
The product of its (nonzero) digits is 81, while the sum is 15.
Adding to 11033000000133 its reverse (33100000033011), we get a palindrome (44133000033144).
The spelling of 11033000000133 in words is "eleven trillion, thirty-three billion, one hundred thirty-three", and thus it is an aban number.
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