Base | Representation |
---|---|
bin | 10100100011001111… |
… | …00011100110100001 |
3 | 1001110220112111012201 |
4 | 22101213203212201 |
5 | 140043422002403 |
6 | 5022443253201 |
7 | 540256645534 |
oct | 122147434641 |
9 | 31426474181 |
10 | 11033000353 |
11 | 4751928511 |
12 | 217ab1a201 |
13 | 106aa1019b |
14 | 769420a1b |
15 | 44890c21d |
hex | 2919e39a1 |
11033000353 has 2 divisors, whose sum is σ = 11033000354. Its totient is φ = 11033000352.
The previous prime is 11033000339. The next prime is 11033000443. The reversal of 11033000353 is 35300033011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6819951889 + 4213048464 = 82583^2 + 64908^2 .
It is an emirp because it is prime and its reverse (35300033011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11033000353 - 213 = 11032992161 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11033000353.
It is not a weakly prime, because it can be changed into another prime (11033000333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516500176 + 5516500177.
It is an arithmetic number, because the mean of its divisors is an integer number (5516500177).
Almost surely, 211033000353 is an apocalyptic number.
It is an amenable number.
11033000353 is a deficient number, since it is larger than the sum of its proper divisors (1).
11033000353 is an equidigital number, since it uses as much as digits as its factorization.
11033000353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 405, while the sum is 19.
Adding to 11033000353 its reverse (35300033011), we get a palindrome (46333033364).
The spelling of 11033000353 in words is "eleven billion, thirty-three million, three hundred fifty-three", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.098 sec. • engine limits •