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110330013301121 = 257249428884129
BaseRepresentation
bin11001000101100000110101…
…010000000011100110000001
3112110122110001022210110221102
4121011200311100003212001
5103430121331401113441
61030352524114104145
732145036403346645
oct3105406520034601
9473573038713842
10110330013301121
1132177772235889
121045a84227b055
1349740ca171433
141d36003190c25
15cb4e0bc7669b
hex645835403981

110330013301121 has 4 divisors (see below), whose sum is σ = 110330442442500. Its totient is φ = 110329584159744.

The previous prime is 110330013301043. The next prime is 110330013301129. The reversal of 110330013301121 is 121103310033011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 80035567987600 + 30294445313521 = 8946260^2 + 5504039^2 .

It is a cyclic number.

It is not a de Polignac number, because 110330013301121 - 214 = 110330013284737 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110330013301093 and 110330013301102.

It is not an unprimeable number, because it can be changed into a prime (110330013301129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214184816 + ... + 214699313.

It is an arithmetic number, because the mean of its divisors is an integer number (27582610610625).

Almost surely, 2110330013301121 is an apocalyptic number.

It is an amenable number.

110330013301121 is a deficient number, since it is larger than the sum of its proper divisors (429141379).

110330013301121 is an equidigital number, since it uses as much as digits as its factorization.

110330013301121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 429141378.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 110330013301121 its reverse (121103310033011), we get a palindrome (231433323334132).

The spelling of 110330013301121 in words is "one hundred ten trillion, three hundred thirty billion, thirteen million, three hundred one thousand, one hundred twenty-one".

Divisors: 1 257249 428884129 110330013301121