1103300310113 has 4 divisors (see below), whose sum is σ = 1103313588420. Its totient is φ = 1103287031808.

The previous prime is 1103300310109. The next prime is 1103300310157. The reversal of 1103300310113 is 3110130033011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 624009943249 + 479290366864 = 789943^2 + 692308^2 .

It is a cyclic number.

It is not a de Polignac number, because 1103300310113 - 2² = 1103300310109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1103300310091 and 1103300310100.

It is not an unprimeable number, because it can be changed into a prime (1103300310193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6513728 + ... + 6680961.

It is an arithmetic number, because the mean of its divisors is an integer number (275828397105).

Almost surely, 2^{1103300310113} is an apocalyptic number.

It is an amenable number.

1103300310113 is a deficient number, since it is larger than the sum of its proper divisors (13278307).

1103300310113 is an equidigital number, since it uses as much as digits as its factorization.

1103300310113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13278306.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1103300310113 its reverse (3110130033011), we get a palindrome (4213430343124).

The spelling of 1103300310113 in words is "one trillion, one hundred three billion, three hundred million, three hundred ten thousand, one hundred thirteen".