11033112113 has 4 divisors (see below), whose sum is σ = 11172771840. Its totient is φ = 10893452388.

The previous prime is 11033112059. The next prime is 11033112127. The reversal of 11033112113 is 31121133011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11033112113 - 2⁶ = 11033112049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11033112091 and 11033112100.

It is not an unprimeable number, because it can be changed into a prime (11033112143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69829745 + ... + 69829902.

It is an arithmetic number, because the mean of its divisors is an integer number (2793192960).

Almost surely, 2^11033112113 is an apocalyptic number.

It is an amenable number.

11033112113 is a deficient number, since it is larger than the sum of its proper divisors (139659727).

11033112113 is an equidigital number, since it uses as much as digits as its factorization.

11033112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 139659726.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11033112113 its reverse (31121133011), we get a palindrome (42154245124).

The spelling of 11033112113 in words is "eleven billion, thirty-three million, one hundred twelve thousand, one hundred thirteen".