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1103313131341 = 4792392302219
BaseRepresentation
bin10000000011100010100…
…101100101011101001101
310220110211210022021111221
4100003202211211131031
5121034041130200331
62202504405243341
7142466061610411
oct20034245453515
93813753267457
101103313131341
11395a04554673
121599b5403551
1380071307515
143b587500d41
151da76799711
hex100e296574d

1103313131341 has 4 divisors (see below), whose sum is σ = 1103315912800. Its totient is φ = 1103310349884.

The previous prime is 1103313131309. The next prime is 1103313131369. The reversal of 1103313131341 is 1431313133011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1103313131341 - 25 = 1103313131309 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1103313161341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 671871 + ... + 1630348.

It is an arithmetic number, because the mean of its divisors is an integer number (275828978200).

Almost surely, 21103313131341 is an apocalyptic number.

It is an amenable number.

1103313131341 is a deficient number, since it is larger than the sum of its proper divisors (2781459).

1103313131341 is an equidigital number, since it uses as much as digits as its factorization.

1103313131341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2781458.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 1103313131341 its reverse (1431313133011), we get a palindrome (2534626264352).

The spelling of 1103313131341 in words is "one trillion, one hundred three billion, three hundred thirteen million, one hundred thirty-one thousand, three hundred forty-one".

Divisors: 1 479239 2302219 1103313131341