1103314505413 has 4 divisors (see below), whose sum is σ = 1103317931808. Its totient is φ = 1103311079020.

The previous prime is 1103314505411. The next prime is 1103314505507. The reversal of 1103314505413 is 3145054133011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1103314505413 - 2¹ = 1103314505411 is a prime.

It is a super-3 number, since 3×1103314505413³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1103314505411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1173523 + ... + 1893088.

It is an arithmetic number, because the mean of its divisors is an integer number (275829482952).

Almost surely, 2^{1103314505413} is an apocalyptic number.

It is an amenable number.

1103314505413 is a deficient number, since it is larger than the sum of its proper divisors (3426395).

1103314505413 is an equidigital number, since it uses as much as digits as its factorization.

1103314505413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3426394.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 1103314505413 its reverse (3145054133011), we get a palindrome (4248368638424).

The spelling of 1103314505413 in words is "one trillion, one hundred three billion, three hundred fourteen million, five hundred five thousand, four hundred thirteen".