Base | Representation |
---|---|
bin | 1010000010001101111010… |
… | …0111111100111100100011 |
3 | 1110001202122110001212120212 |
4 | 2200203132213330330203 |
5 | 2421232004011000311 |
6 | 35244330455124335 |
7 | 2216060153245466 |
oct | 240433647747443 |
9 | 43052573055525 |
10 | 11033211031331 |
11 | 3574181aa0345 |
12 | 12a23880736ab |
13 | 620572b1aa98 |
14 | 2a202023b2dd |
15 | 141eec15ec8b |
hex | a08de9fcf23 |
11033211031331 has 2 divisors, whose sum is σ = 11033211031332. Its totient is φ = 11033211031330.
The previous prime is 11033211031273. The next prime is 11033211031351. The reversal of 11033211031331 is 13313011233011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11033211031331 - 218 = 11033210769187 is a prime.
It is a super-2 number, since 2×110332110313312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11033211031297 and 11033211031306.
It is not a weakly prime, because it can be changed into another prime (11033211031351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516605515665 + 5516605515666.
It is an arithmetic number, because the mean of its divisors is an integer number (5516605515666).
Almost surely, 211033211031331 is an apocalyptic number.
11033211031331 is a deficient number, since it is larger than the sum of its proper divisors (1).
11033211031331 is an equidigital number, since it uses as much as digits as its factorization.
11033211031331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 11033211031331 its reverse (13313011233011), we get a palindrome (24346222264342).
The spelling of 11033211031331 in words is "eleven trillion, thirty-three billion, two hundred eleven million, thirty-one thousand, three hundred thirty-one".
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