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1103332011029 is a prime number
BaseRepresentation
bin10000000011100011101…
…101100110110000010101
310220110220002211110120122
4100003203231212300111
5121034110443323104
62202510322041325
7142466411232263
oct20034355466025
93813802743518
101103332011029
11395a1417a216
121599bb7a9245
13800751b7a31
143b589c17433
151da782786be
hex100e3b66c15

1103332011029 has 2 divisors, whose sum is σ = 1103332011030. Its totient is φ = 1103332011028.

The previous prime is 1103332010993. The next prime is 1103332011043. The reversal of 1103332011029 is 9201102333011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 979130040100 + 124201970929 = 989510^2 + 352423^2 .

It is an emirp because it is prime and its reverse (9201102333011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1103332011029 - 216 = 1103331945493 is a prime.

It is a super-2 number, since 2×11033320110292 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1103332010989 and 1103332011007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1103332011049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551666005514 + 551666005515.

It is an arithmetic number, because the mean of its divisors is an integer number (551666005515).

Almost surely, 21103332011029 is an apocalyptic number.

It is an amenable number.

1103332011029 is a deficient number, since it is larger than the sum of its proper divisors (1).

1103332011029 is an equidigital number, since it uses as much as digits as its factorization.

1103332011029 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 26.

The spelling of 1103332011029 in words is "one trillion, one hundred three billion, three hundred thirty-two million, eleven thousand, twenty-nine".