Base | Representation |
---|---|
bin | 1010000010001110010110… |
… | …0110011100101111011001 |
3 | 1110001202221121022110010201 |
4 | 2200203211212130233121 |
5 | 2421232223441442120 |
6 | 35244350235542201 |
7 | 2216063104156006 |
oct | 240434546345731 |
9 | 43052847273121 |
10 | 11033328077785 |
11 | 3574232075052 |
12 | 12a23bb2ba961 |
13 | 62059114c540 |
14 | 2a20319c88ad |
15 | 14200758040a |
hex | a08e599cbd9 |
11033328077785 has 16 divisors (see below), whose sum is σ = 14258523976704. Its totient is φ = 8147648866752.
The previous prime is 11033328077771. The next prime is 11033328077789. The reversal of 11033328077785 is 58777082333011.
11033328077785 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 11033328077785 - 25 = 11033328077753 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11033328077789) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26035704 + ... + 26456086.
It is an arithmetic number, because the mean of its divisors is an integer number (891157748544).
Almost surely, 211033328077785 is an apocalyptic number.
It is an amenable number.
11033328077785 is a deficient number, since it is larger than the sum of its proper divisors (3225195898919).
11033328077785 is a wasteful number, since it uses less digits than its factorization.
11033328077785 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 824184.
The product of its (nonzero) digits is 5927040, while the sum is 55.
The spelling of 11033328077785 in words is "eleven trillion, thirty-three billion, three hundred twenty-eight million, seventy-seven thousand, seven hundred eighty-five".
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