Base | Representation |
---|---|
bin | 10000000011100011110… |
… | …101101000001111111101 |
3 | 10220110220020210022201121 |
4 | 100003203311220033331 |
5 | 121034112013124201 |
6 | 2202510435110541 |
7 | 142466435142256 |
oct | 20034365501775 |
9 | 3813806708647 |
10 | 1103334114301 |
11 | 395a15386461 |
12 | 159a00442451 |
13 | 80075773183 |
14 | 3b58a203b2d |
15 | 1da785419a1 |
hex | 100e3d683fd |
1103334114301 has 2 divisors, whose sum is σ = 1103334114302. Its totient is φ = 1103334114300.
The previous prime is 1103334114199. The next prime is 1103334114307. The reversal of 1103334114301 is 1034114333011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1073971578276 + 29362536025 = 1036326^2 + 171355^2 .
It is a cyclic number.
It is not a de Polignac number, because 1103334114301 - 29 = 1103334113789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1103334114307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551667057150 + 551667057151.
It is an arithmetic number, because the mean of its divisors is an integer number (551667057151).
Almost surely, 21103334114301 is an apocalyptic number.
It is an amenable number.
1103334114301 is a deficient number, since it is larger than the sum of its proper divisors (1).
1103334114301 is an equidigital number, since it uses as much as digits as its factorization.
1103334114301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1103334114301 its reverse (1034114333011), we get a palindrome (2137448447312).
The spelling of 1103334114301 in words is "one trillion, one hundred three billion, three hundred thirty-four million, one hundred fourteen thousand, three hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •