Base | Representation |
---|---|
bin | 110011011000011001… |
… | …1010101101010000111 |
3 | 101112210210222122012001 |
4 | 1212300303111222013 |
5 | 3301434122233341 |
6 | 122404550210131 |
7 | 10654224120055 |
oct | 1466063255207 |
9 | 345723878161 |
10 | 110340430471 |
11 | 42882329607 |
12 | 19474953947 |
13 | a535bb245b |
14 | 54aa4bd1d5 |
15 | 2d0be40d31 |
hex | 19b0cd5a87 |
110340430471 has 2 divisors, whose sum is σ = 110340430472. Its totient is φ = 110340430470.
The previous prime is 110340430429. The next prime is 110340430493. The reversal of 110340430471 is 174034043011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110340430471 - 213 = 110340422279 is a prime.
It is a super-3 number, since 3×1103404304713 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110340430771) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55170215235 + 55170215236.
It is an arithmetic number, because the mean of its divisors is an integer number (55170215236).
Almost surely, 2110340430471 is an apocalyptic number.
110340430471 is a deficient number, since it is larger than the sum of its proper divisors (1).
110340430471 is an equidigital number, since it uses as much as digits as its factorization.
110340430471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 110340430471 its reverse (174034043011), we get a palindrome (284374473482).
The spelling of 110340430471 in words is "one hundred ten billion, three hundred forty million, four hundred thirty thousand, four hundred seventy-one".
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