1103414042131 has 4 divisors (see below), whose sum is σ = 1107810114264. Its totient is φ = 1099017970000.

The previous prime is 1103414042119. The next prime is 1103414042177. The reversal of 1103414042131 is 1312404143011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1103414042131 - 2¹⁵ = 1103414009363 is a prime.

It is a super-2 number, since 2×1103414042131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1103414042096 and 1103414042105.

It is not an unprimeable number, because it can be changed into a prime (1103414042231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2198035690 + ... + 2198036191.

It is an arithmetic number, because the mean of its divisors is an integer number (276952528566).

Almost surely, 2^{1103414042131} is an apocalyptic number.

1103414042131 is a deficient number, since it is larger than the sum of its proper divisors (4396072133).

1103414042131 is an equidigital number, since it uses as much as digits as its factorization.

1103414042131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4396072132.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1103414042131 its reverse (1312404143011), we get a palindrome (2415818185142).

The spelling of 1103414042131 in words is "one trillion, one hundred three billion, four hundred fourteen million, forty-two thousand, one hundred thirty-one".