Base | Representation |
---|---|
bin | 10100100011011000… |
… | …01011111011100101 |
3 | 1001110222211011011221 |
4 | 22101230023323211 |
5 | 140044224322432 |
6 | 5022525300341 |
7 | 540303162313 |
oct | 122154137345 |
9 | 31428734157 |
10 | 11034214117 |
11 | 4752587423 |
12 | 217b4046b1 |
13 | 106b0467a4 |
14 | 7696590b3 |
15 | 448a9bb97 |
hex | 291b0bee5 |
11034214117 has 2 divisors, whose sum is σ = 11034214118. Its totient is φ = 11034214116.
The previous prime is 11034214099. The next prime is 11034214151. The reversal of 11034214117 is 71141243011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10430332641 + 603881476 = 102129^2 + 24574^2 .
It is a cyclic number.
It is not a de Polignac number, because 11034214117 - 219 = 11033689829 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11034214091 and 11034214100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11014214117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5517107058 + 5517107059.
It is an arithmetic number, because the mean of its divisors is an integer number (5517107059).
Almost surely, 211034214117 is an apocalyptic number.
It is an amenable number.
11034214117 is a deficient number, since it is larger than the sum of its proper divisors (1).
11034214117 is an equidigital number, since it uses as much as digits as its factorization.
11034214117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 25.
Adding to 11034214117 its reverse (71141243011), we get a palindrome (82175457128).
The spelling of 11034214117 in words is "eleven billion, thirty-four million, two hundred fourteen thousand, one hundred seventeen".
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