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1103433124214 = 22572146757051
BaseRepresentation
bin10000000011101001101…
…111010100100101110110
310220111011011002112210102
4100003221233110211312
5121034312334433324
62202524333154102
7142502046542021
oct20035157244566
93814134075712
101103433124214
11395a66261033
12159a2962b932
138009012b115
143b5994181b8
151da8209cdae
hex100e9bd4976

1103433124214 has 8 divisors (see below), whose sum is σ = 1661589958248. Its totient is φ = 549569804800.

The previous prime is 1103433124193. The next prime is 1103433124217. The reversal of 1103433124214 is 4124213343011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×11034331242142 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1103433124217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1073378012 + ... + 1073379039.

It is an arithmetic number, because the mean of its divisors is an integer number (207698744781).

Almost surely, 21103433124214 is an apocalyptic number.

1103433124214 is a deficient number, since it is larger than the sum of its proper divisors (558156834034).

1103433124214 is a wasteful number, since it uses less digits than its factorization.

1103433124214 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2146757310.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1103433124214 its reverse (4124213343011), we get a palindrome (5227646467225).

The spelling of 1103433124214 in words is "one trillion, one hundred three billion, four hundred thirty-three million, one hundred twenty-four thousand, two hundred fourteen".

Divisors: 1 2 257 514 2146757051 4293514102 551716562107 1103433124214