Base | Representation |
---|---|
bin | 10000000011101001101… |
… | …111010100100101110110 |
3 | 10220111011011002112210102 |
4 | 100003221233110211312 |
5 | 121034312334433324 |
6 | 2202524333154102 |
7 | 142502046542021 |
oct | 20035157244566 |
9 | 3814134075712 |
10 | 1103433124214 |
11 | 395a66261033 |
12 | 159a2962b932 |
13 | 8009012b115 |
14 | 3b5994181b8 |
15 | 1da8209cdae |
hex | 100e9bd4976 |
1103433124214 has 8 divisors (see below), whose sum is σ = 1661589958248. Its totient is φ = 549569804800.
The previous prime is 1103433124193. The next prime is 1103433124217. The reversal of 1103433124214 is 4124213343011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×11034331242142 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1103433124217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1073378012 + ... + 1073379039.
It is an arithmetic number, because the mean of its divisors is an integer number (207698744781).
Almost surely, 21103433124214 is an apocalyptic number.
1103433124214 is a deficient number, since it is larger than the sum of its proper divisors (558156834034).
1103433124214 is a wasteful number, since it uses less digits than its factorization.
1103433124214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2146757310.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1103433124214 its reverse (4124213343011), we get a palindrome (5227646467225).
The spelling of 1103433124214 in words is "one trillion, one hundred three billion, four hundred thirty-three million, one hundred twenty-four thousand, two hundred fourteen".
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