Base | Representation |
---|---|
bin | 10100100011011110… |
… | …01011110100110001 |
3 | 1001111001022002100220 |
4 | 22101233023310301 |
5 | 140044430000423 |
6 | 5022554203253 |
7 | 540312644664 |
oct | 122157136461 |
9 | 31431262326 |
10 | 11035000113 |
11 | 4752a73a05 |
12 | 217b723529 |
13 | 106b260487 |
14 | 7697c16db |
15 | 448ba49e3 |
hex | 291bcbd31 |
11035000113 has 8 divisors (see below), whose sum is σ = 14788021248. Its totient is φ = 7319322864.
The previous prime is 11035000111. The next prime is 11035000117. The reversal of 11035000113 is 31100053011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11035000113 - 21 = 11035000111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11035000092 and 11035000101.
It is not an unprimeable number, because it can be changed into a prime (11035000111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9335281 + ... + 9336462.
It is an arithmetic number, because the mean of its divisors is an integer number (1848502656).
Almost surely, 211035000113 is an apocalyptic number.
It is an amenable number.
11035000113 is a deficient number, since it is larger than the sum of its proper divisors (3753021135).
11035000113 is a wasteful number, since it uses less digits than its factorization.
11035000113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18671943.
The product of its (nonzero) digits is 45, while the sum is 15.
Adding to 11035000113 its reverse (31100053011), we get a palindrome (42135053124).
The spelling of 11035000113 in words is "eleven billion, thirty-five million, one hundred thirteen", and thus it is an aban number.
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