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11035000114 = 25517500057
BaseRepresentation
bin10100100011011110…
…01011110100110010
31001111001022002100221
422101233023310302
5140044430000424
65022554203254
7540312644665
oct122157136462
931431262327
1011035000114
114752a73a06
12217b72352a
13106b260488
147697c16dc
15448ba49e4
hex291bcbd32

11035000114 has 4 divisors (see below), whose sum is σ = 16552500174. Its totient is φ = 5517500056.

The previous prime is 11035000111. The next prime is 11035000117. The reversal of 11035000114 is 41100053011.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (11035000111) and next prime (11035000117).

It can be written as a sum of positive squares in only one way, i.e., 8338794489 + 2696205625 = 91317^2 + 51925^2 .

It is not an unprimeable number, because it can be changed into a prime (11035000111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2758750027 + ... + 2758750030.

Almost surely, 211035000114 is an apocalyptic number.

11035000114 is a deficient number, since it is larger than the sum of its proper divisors (5517500060).

11035000114 is an equidigital number, since it uses as much as digits as its factorization.

11035000114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5517500059.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 11035000114 its reverse (41100053011), we get a palindrome (52135053125).

The spelling of 11035000114 in words is "eleven billion, thirty-five million, one hundred fourteen", and thus it is an aban number.

Divisors: 1 2 5517500057 11035000114