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110401211124403 is a prime number
BaseRepresentation
bin11001000110100011001000…
…111110001100101010110011
3112110220020211020001122110021
4121012203020332030222303
5103432303140021440103
61030445341034344311
732153136634020523
oct3106431076145263
9473806736048407
10110401211124403
11321a4988587251
12104705b228b097
13497aa357ca554
141d39638ccb683
15cb6bc75e2bbd
hex6468c8f8cab3

110401211124403 has 2 divisors, whose sum is σ = 110401211124404. Its totient is φ = 110401211124402.

The previous prime is 110401211124377. The next prime is 110401211124467. The reversal of 110401211124403 is 304421112104011.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110401211124403 is a prime.

It is not a weakly prime, because it can be changed into another prime (110401211124703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55200605562201 + 55200605562202.

It is an arithmetic number, because the mean of its divisors is an integer number (55200605562202).

Almost surely, 2110401211124403 is an apocalyptic number.

110401211124403 is a deficient number, since it is larger than the sum of its proper divisors (1).

110401211124403 is an equidigital number, since it uses as much as digits as its factorization.

110401211124403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 110401211124403 its reverse (304421112104011), we get a palindrome (414822323228414).

The spelling of 110401211124403 in words is "one hundred ten trillion, four hundred one billion, two hundred eleven million, one hundred twenty-four thousand, four hundred three".