11040131 has 2 divisors, whose sum is σ = 11040132. Its totient is φ = 11040130.

The previous prime is 11040119. The next prime is 11040151. The reversal of 11040131 is 13104011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11040131 - 2⁶ = 11040067 is a prime.

It is a super-2 number, since 2×11040131² = 243768984994322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11040151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520065 + 5520066.

It is an arithmetic number, because the mean of its divisors is an integer number (5520066).

Almost surely, 2^11040131 is an apocalyptic number.

11040131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11040131 is an equidigital number, since it uses as much as digits as its factorization.

11040131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 11040131 is about 3322.6692582922. The cubic root of 11040131 is about 222.6681370196.

Adding to 11040131 its reverse (13104011), we get a palindrome (24144142).

The spelling of 11040131 in words is "eleven million, forty thousand, one hundred thirty-one".