110401411 has 2 divisors, whose sum is σ = 110401412. Its totient is φ = 110401410.

The previous prime is 110401393. The next prime is 110401441. The reversal of 110401411 is 114104011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 110401411 - 2¹³ = 110393219 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110401391 and 110401400.

It is not a weakly prime, because it can be changed into another prime (110401441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55200705 + 55200706.

It is an arithmetic number, because the mean of its divisors is an integer number (55200706).

Almost surely, 2^110401411 is an apocalyptic number.

110401411 is a deficient number, since it is larger than the sum of its proper divisors (1).

110401411 is an equidigital number, since it uses as much as digits as its factorization.

110401411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16, while the sum is 13.

The square root of 110401411 is about 10507.2075738514. The cubic root of 110401411 is about 479.7241050507.

Adding to 110401411 its reverse (114104011), we get a palindrome (224505422).

The spelling of 110401411 in words is "one hundred ten million, four hundred one thousand, four hundred eleven".