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110401441331 is a prime number
BaseRepresentation
bin110011011010001110…
…0000100111000110011
3101112222001210022100112
41212310130010320303
53302100232110311
6122415010011535
710655564524226
oct1466434047063
9345861708315
10110401441331
114290380aa05
1219491276bab
13a54572455c
1454b46415bd
152d1249328b
hex19b4704e33

110401441331 has 2 divisors, whose sum is σ = 110401441332. Its totient is φ = 110401441330.

The previous prime is 110401441309. The next prime is 110401441351. The reversal of 110401441331 is 133144104011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110401441331 is a prime.

It is a super-2 number, since 2×1104014413312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110401441297 and 110401441306.

It is not a weakly prime, because it can be changed into another prime (110401441351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55200720665 + 55200720666.

It is an arithmetic number, because the mean of its divisors is an integer number (55200720666).

Almost surely, 2110401441331 is an apocalyptic number.

110401441331 is a deficient number, since it is larger than the sum of its proper divisors (1).

110401441331 is an equidigital number, since it uses as much as digits as its factorization.

110401441331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 110401441331 its reverse (133144104011), we get a palindrome (243545545342).

The spelling of 110401441331 in words is "one hundred ten billion, four hundred one million, four hundred forty-one thousand, three hundred thirty-one".