Search a number
-
+
1104024311323 = 4392514861757
BaseRepresentation
bin10000000100001100111…
…110100001011000011011
310220112200100111222001021
4100010030332201120123
5121042020210430243
62203103132303311
7142522515544423
oct20041476413033
93815610458037
101104024311323
11396239a3a71a
12159b73611b37
138015575c58b
143b613b49483
151dab8e296ed
hex1010cfa161b

1104024311323 has 4 divisors (see below), whose sum is σ = 1106539173520. Its totient is φ = 1101509449128.

The previous prime is 1104024311309. The next prime is 1104024311371. The reversal of 1104024311323 is 3231134204011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1104024311323 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1104024311303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1257430440 + ... + 1257431317.

It is an arithmetic number, because the mean of its divisors is an integer number (276634793380).

Almost surely, 21104024311323 is an apocalyptic number.

1104024311323 is a deficient number, since it is larger than the sum of its proper divisors (2514862197).

1104024311323 is an equidigital number, since it uses as much as digits as its factorization.

1104024311323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2514862196.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1104024311323 its reverse (3231134204011), we get a palindrome (4335158515334).

The spelling of 1104024311323 in words is "one trillion, one hundred four billion, twenty-four million, three hundred eleven thousand, three hundred twenty-three".

Divisors: 1 439 2514861757 1104024311323