11040313 has 2 divisors, whose sum is σ = 11040314. Its totient is φ = 11040312.

The previous prime is 11040241. The next prime is 11040317. The reversal of 11040313 is 31304011.

11040313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5531904 + 5508409 = 2352^2 + 2347^2 .

It is a cyclic number.

It is not a de Polignac number, because 11040313 - 2¹³ = 11032121 is a prime.

It is a super-2 number, since 2×11040313² = 243777022275938, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11040293 and 11040302.

It is not a weakly prime, because it can be changed into another prime (11040317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520156 + 5520157.

It is an arithmetic number, because the mean of its divisors is an integer number (5520157).

Almost surely, 2^11040313 is an apocalyptic number.

It is an amenable number.

11040313 is a deficient number, since it is larger than the sum of its proper divisors (1).

11040313 is an equidigital number, since it uses as much as digits as its factorization.

11040313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 11040313 is about 3322.6966457984. The cubic root of 11040313 is about 222.6693605974.

Adding to 11040313 its reverse (31304011), we get a palindrome (42344324).

The spelling of 11040313 in words is "eleven million, forty thousand, three hundred thirteen".