Base | Representation |
---|---|
bin | 1010000010101000011000… |
… | …0000000001011000000101 |
3 | 1110002102222110202022112111 |
4 | 2200222012000001120011 |
5 | 2421341030402301201 |
6 | 35251503354421021 |
7 | 2216431163333230 |
oct | 240520600013005 |
9 | 43072873668474 |
10 | 11040314103301 |
11 | 357719754445a |
12 | 12a382aa31771 |
13 | 6211355a1852 |
14 | 2a24d5748417 |
15 | 1422b5a38b51 |
hex | a0a86001605 |
11040314103301 has 8 divisors (see below), whose sum is σ = 12670294728960. Its totient is φ = 9423531701808.
The previous prime is 11040314103283. The next prime is 11040314103407. The reversal of 11040314103301 is 10330141304011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11040314103301 - 211 = 11040314101253 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11040314103601) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3299554246 + ... + 3299557591.
It is an arithmetic number, because the mean of its divisors is an integer number (1583786841120).
Almost surely, 211040314103301 is an apocalyptic number.
It is an amenable number.
11040314103301 is a deficient number, since it is larger than the sum of its proper divisors (1629980625659).
11040314103301 is an equidigital number, since it uses as much as digits as its factorization.
11040314103301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6599112083.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 11040314103301 its reverse (10330141304011), we get a palindrome (21370455407312).
The spelling of 11040314103301 in words is "eleven trillion, forty billion, three hundred fourteen million, one hundred three thousand, three hundred one".
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