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1104031432957 is a prime number
BaseRepresentation
bin10000000100001101011…
…001101100000011111101
310220112200211220210002111
4100010031121230003331
5121042024021323312
62203103545054021
7142522633225255
oct20041531540375
93815624823074
101104031432957
11396242a64272
12159b75a87311
1380157083c6b
143b614a80965
151dab98848a7
hex1010d66c0fd

1104031432957 has 2 divisors, whose sum is σ = 1104031432958. Its totient is φ = 1104031432956.

The previous prime is 1104031432951. The next prime is 1104031433081. The reversal of 1104031432957 is 7592341304011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 891336139236 + 212695293721 = 944106^2 + 461189^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1104031432957 is a prime.

It is a super-3 number, since 3×11040314329573 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1104031432951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552015716478 + 552015716479.

It is an arithmetic number, because the mean of its divisors is an integer number (552015716479).

Almost surely, 21104031432957 is an apocalyptic number.

It is an amenable number.

1104031432957 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104031432957 is an equidigital number, since it uses as much as digits as its factorization.

1104031432957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90720, while the sum is 40.

Adding to 1104031432957 its reverse (7592341304011), we get a palindrome (8696372736968).

The spelling of 1104031432957 in words is "one trillion, one hundred four billion, thirty-one million, four hundred thirty-two thousand, nine hundred fifty-seven".