11040340433 has 2 divisors, whose sum is σ = 11040340434. Its totient is φ = 11040340432.

The previous prime is 11040340391. The next prime is 11040340453. The reversal of 11040340433 is 33404304011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8985712849 + 2054627584 = 94793^2 + 45328^2 .

It is a cyclic number.

It is not a de Polignac number, because 11040340433 - 2⁸ = 11040340177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11040340399 and 11040340408.

It is not a weakly prime, because it can be changed into another prime (11040340453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520170216 + 5520170217.

It is an arithmetic number, because the mean of its divisors is an integer number (5520170217).

Almost surely, 2^11040340433 is an apocalyptic number.

It is an amenable number.

11040340433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11040340433 is an equidigital number, since it uses as much as digits as its factorization.

11040340433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 11040340433 its reverse (33404304011), we get a palindrome (44444644444).

The spelling of 11040340433 in words is "eleven billion, forty million, three hundred forty thousand, four hundred thirty-three".