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1104041011057 is a prime number
BaseRepresentation
bin10000000100001101111…
…110001110011101110001
310220112201111221101202221
4100010031332032131301
5121042033444323212
62203104530241041
7142523110516615
oct20041576163561
93815644841687
101104041011057
11396248406456
12159b79126181
138015905878a
143b616055345
151daba627807
hex1010df8e771

1104041011057 has 2 divisors, whose sum is σ = 1104041011058. Its totient is φ = 1104041011056.

The previous prime is 1104041010973. The next prime is 1104041011133. The reversal of 1104041011057 is 7501101404011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1090188662641 + 13852348416 = 1044121^2 + 117696^2 .

It is a cyclic number.

It is not a de Polignac number, because 1104041011057 - 223 = 1104032622449 is a prime.

It is not a weakly prime, because it can be changed into another prime (1104041011357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552020505528 + 552020505529.

It is an arithmetic number, because the mean of its divisors is an integer number (552020505529).

Almost surely, 21104041011057 is an apocalyptic number.

It is an amenable number.

1104041011057 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104041011057 is an equidigital number, since it uses as much as digits as its factorization.

1104041011057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 560, while the sum is 25.

Adding to 1104041011057 its reverse (7501101404011), we get a palindrome (8605142415068).

The spelling of 1104041011057 in words is "one trillion, one hundred four billion, forty-one million, eleven thousand, fifty-seven".