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11040411433 = 49122485563
BaseRepresentation
bin10100100100000111…
…10100111100101001
31001111102111000022011
422102003310330221
5140102321131213
65023310155521
7540406643302
oct122203647451
931442430264
1011040411433
11475602a577
1221814b2ba1
13106c40653c
1476a3cd7a9
154493c303d
hex2920f4f29

11040411433 has 4 divisors (see below), whose sum is σ = 11062897488. Its totient is φ = 11017925380.

The previous prime is 11040411419. The next prime is 11040411467. The reversal of 11040411433 is 33411404011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11040411433 - 221 = 11038314281 is a prime.

It is a super-2 number, since 2×110404114332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11040411233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11242291 + ... + 11243272.

It is an arithmetic number, because the mean of its divisors is an integer number (2765724372).

Almost surely, 211040411433 is an apocalyptic number.

It is an amenable number.

11040411433 is a deficient number, since it is larger than the sum of its proper divisors (22486055).

11040411433 is an equidigital number, since it uses as much as digits as its factorization.

11040411433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22486054.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 11040411433 its reverse (33411404011), we get a palindrome (44451815444).

The spelling of 11040411433 in words is "eleven billion, forty million, four hundred eleven thousand, four hundred thirty-three".

Divisors: 1 491 22485563 11040411433