Base | Representation |
---|---|
bin | 10000000100001110001… |
… | …010000101101111010001 |
3 | 10220112201201210101212112 |
4 | 100010032022011233101 |
5 | 121042040243333131 |
6 | 2203105121035105 |
7 | 142523146121621 |
oct | 20041612055721 |
9 | 3815651711775 |
10 | 1104044121041 |
11 | 39624a13aa94 |
12 | 159b7a185a95 |
13 | 801598a71c4 |
14 | 3b616624881 |
15 | 1dabaa3e02b |
hex | 1010e285bd1 |
1104044121041 has 2 divisors, whose sum is σ = 1104044121042. Its totient is φ = 1104044121040.
The previous prime is 1104044121017. The next prime is 1104044121053. The reversal of 1104044121041 is 1401214404011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 856542846016 + 247501275025 = 925496^2 + 497495^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1104044121041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1104044120998 and 1104044121016.
It is not a weakly prime, because it can be changed into another prime (1104044121001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552022060520 + 552022060521.
It is an arithmetic number, because the mean of its divisors is an integer number (552022060521).
Almost surely, 21104044121041 is an apocalyptic number.
It is an amenable number.
1104044121041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104044121041 is an equidigital number, since it uses as much as digits as its factorization.
1104044121041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 512, while the sum is 23.
Adding to 1104044121041 its reverse (1401214404011), we get a palindrome (2505258525052).
The spelling of 1104044121041 in words is "one trillion, one hundred four billion, forty-four million, one hundred twenty-one thousand, forty-one".
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