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1104099052499 is a prime number
BaseRepresentation
bin10000000100010001011…
…011101000101111010011
310220112212120011012122222
4100010101123220233103
5121042143324134444
62203114402251255
7142524414045632
oct20042133505723
93815776135588
101104099052499
11396278149893
12159b94656b2b
138016809b121
143b61da43519
151dac078eeee
hex101116e8bd3

1104099052499 has 2 divisors, whose sum is σ = 1104099052500. Its totient is φ = 1104099052498.

The previous prime is 1104099052471. The next prime is 1104099052501. The reversal of 1104099052499 is 9942509904011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1104099052499 is a prime.

Together with 1104099052501, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1104099052499.

It is not a weakly prime, because it can be changed into another prime (1104099252499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552049526249 + 552049526250.

It is an arithmetic number, because the mean of its divisors is an integer number (552049526250).

Almost surely, 21104099052499 is an apocalyptic number.

1104099052499 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104099052499 is an equidigital number, since it uses as much as digits as its factorization.

1104099052499 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1049760, while the sum is 53.

The spelling of 1104099052499 in words is "one trillion, one hundred four billion, ninety-nine million, fifty-two thousand, four hundred ninety-nine".