1104103121 has 4 divisors (see below), whose sum is σ = 1204476144. Its totient is φ = 1003730100.

The previous prime is 1104103103. The next prime is 1104103151. The reversal of 1104103121 is 1213014011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1213014011 = 11 ⋅110274001.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1104103121 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1104103096 and 1104103105.

It is not an unprimeable number, because it can be changed into a prime (1104103151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50186495 + ... + 50186516.

It is an arithmetic number, because the mean of its divisors is an integer number (301119036).

Almost surely, 2^1104103121 is an apocalyptic number.

1104103121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1104103121 is a deficient number, since it is larger than the sum of its proper divisors (100373023).

1104103121 is a wasteful number, since it uses less digits than its factorization.

1104103121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100373022.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 1104103121 is about 33228.0472041316. The cubic root of 1104103121 is about 1033.5620290094.

Adding to 1104103121 its reverse (1213014011), we get a palindrome (2317117132).

The spelling of 1104103121 in words is "one billion, one hundred four million, one hundred three thousand, one hundred twenty-one".