Base | Representation |
---|---|
bin | 10100100100001101… |
… | …00100101100111011 |
3 | 1001111110211120210202 |
4 | 22102012210230323 |
5 | 140103012200243 |
6 | 5023333432415 |
7 | 540416032145 |
oct | 122206445473 |
9 | 31443746722 |
10 | 11041131323 |
11 | 4756481422 |
12 | 218179b70b |
13 | 106c5c9101 |
14 | 76a539c95 |
15 | 4494b64b8 |
hex | 2921a4b3b |
11041131323 has 2 divisors, whose sum is σ = 11041131324. Its totient is φ = 11041131322.
The previous prime is 11041131307. The next prime is 11041131341. The reversal of 11041131323 is 32313114011.
It is a weak prime.
It is an emirp because it is prime and its reverse (32313114011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11041131323 - 24 = 11041131307 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 11041131295 and 11041131304.
It is not a weakly prime, because it can be changed into another prime (11041130323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520565661 + 5520565662.
It is an arithmetic number, because the mean of its divisors is an integer number (5520565662).
Almost surely, 211041131323 is an apocalyptic number.
11041131323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11041131323 is an equidigital number, since it uses as much as digits as its factorization.
11041131323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 11041131323 its reverse (32313114011), we get a palindrome (43354245334).
The spelling of 11041131323 in words is "eleven billion, forty-one million, one hundred thirty-one thousand, three hundred twenty-three".
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